create an incremental counter in the stored procedure

Hello, I have a following SP
I want to add an extra field "ranking" that just increments the row number.
Another feature would be: if several users have an equal totalvalue, they
should have an equal ranking number. the rankings following users would have
to be adjusted as well. thanks

SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS OFF
GO

CREATE PROCEDURE [dbo].[Rankings]
@.iErrorCode int OUTPUT
AS

SELECT top 30
###COUNTER##,
[user],
[totalvalue], [cash], [stocksvalue]

FROM [dbo].[users]
ORDER BY totalvalue DESC

SELECT @.iErrorCode=@.@.ERROR

GO
SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GOThere is more than one way to rank a set with tied values.

CREATE TABLE Users (userid INTEGER PRIMARY KEY, totalvalue NUMERIC(10,2) NOT
NULL, cash NUMERIC(10,2) NOT NULL, stocksvalue NUMERIC(10,2) NOT NULL)

INSERT INTO Users VALUES (101,1010,100,99)
INSERT INTO Users VALUES (102,2020,100,99)
INSERT INTO Users VALUES (103,3030,100,99)
INSERT INTO Users VALUES (104,3030,100,99)
INSERT INTO Users VALUES (105,1002,100,99)
INSERT INTO Users VALUES (106,1002,100,99)
INSERT INTO Users VALUES (107,1002,100,99)
INSERT INTO Users VALUES (108,1002,100,99)
INSERT INTO Users VALUES (109,1000,100,99)

See if this gives the result you expect:

SELECT COUNT(U2.totalvalue)+1 AS ranking,
U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
FROM Users AS U1
LEFT JOIN Users AS U2
ON U1.totalvalue < U2.totalvalue
GROUP BY U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
ORDER BY ranking, U1.userid

Result:

ranking userid totalvalue cash stocksvalue
---- ---- ---- ---- ----
1 103 3030.00 100.00 99.00
1 104 3030.00 100.00 99.00
3 102 2020.00 100.00 99.00
4 101 1010.00 100.00 99.00
5 105 1002.00 100.00 99.00
5 106 1002.00 100.00 99.00
5 107 1002.00 100.00 99.00
5 108 1002.00 100.00 99.00
9 109 1000.00 100.00 99.00

(9 row(s) affected)

Or maybe this:

SELECT COUNT(DISTINCT U2.totalvalue) AS ranking,
U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
FROM Users AS U1
LEFT JOIN Users AS U2
ON U1.totalvalue <= U2.totalvalue
GROUP BY U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
ORDER BY ranking, U1.userid

Result:

ranking userid totalvalue cash stocksvalue
---- ---- ---- ---- ----
1 103 3030.00 100.00 99.00
1 104 3030.00 100.00 99.00
2 102 2020.00 100.00 99.00
3 101 1010.00 100.00 99.00
4 105 1002.00 100.00 99.00
4 106 1002.00 100.00 99.00
4 107 1002.00 100.00 99.00
4 108 1002.00 100.00 99.00
5 109 1000.00 100.00 99.00

(9 row(s) affected)

--
David Portas
SQL Server MVP
--|||thank you! it works fine.

"David Portas" <REMOVE_BEFORE_REPLYING_dportas@.acm.org> schrieb im
Newsbeitrag news:1pmdnW4hl-GFFt3dRVn-uA@.giganews.com...
> There is more than one way to rank a set with tied values.
> CREATE TABLE Users (userid INTEGER PRIMARY KEY, totalvalue NUMERIC(10,2)
NOT
> NULL, cash NUMERIC(10,2) NOT NULL, stocksvalue NUMERIC(10,2) NOT NULL)
> INSERT INTO Users VALUES (101,1010,100,99)
> INSERT INTO Users VALUES (102,2020,100,99)
> INSERT INTO Users VALUES (103,3030,100,99)
> INSERT INTO Users VALUES (104,3030,100,99)
> INSERT INTO Users VALUES (105,1002,100,99)
> INSERT INTO Users VALUES (106,1002,100,99)
> INSERT INTO Users VALUES (107,1002,100,99)
> INSERT INTO Users VALUES (108,1002,100,99)
> INSERT INTO Users VALUES (109,1000,100,99)
> See if this gives the result you expect:
> SELECT COUNT(U2.totalvalue)+1 AS ranking,
> U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
> FROM Users AS U1
> LEFT JOIN Users AS U2
> ON U1.totalvalue < U2.totalvalue
> GROUP BY U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
> ORDER BY ranking, U1.userid
> Result:
> ranking userid totalvalue cash stocksvalue
> ---- ---- ---- ---- ----
> 1 103 3030.00 100.00 99.00
> 1 104 3030.00 100.00 99.00
> 3 102 2020.00 100.00 99.00
> 4 101 1010.00 100.00 99.00
> 5 105 1002.00 100.00 99.00
> 5 106 1002.00 100.00 99.00
> 5 107 1002.00 100.00 99.00
> 5 108 1002.00 100.00 99.00
> 9 109 1000.00 100.00 99.00
> (9 row(s) affected)
> Or maybe this:
> SELECT COUNT(DISTINCT U2.totalvalue) AS ranking,
> U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
> FROM Users AS U1
> LEFT JOIN Users AS U2
> ON U1.totalvalue <= U2.totalvalue
> GROUP BY U1.userid, U1.totalvalue, U1.cash, U1.stocksvalue
> ORDER BY ranking, U1.userid
> Result:
> ranking userid totalvalue cash stocksvalue
> ---- ---- ---- ---- ----
> 1 103 3030.00 100.00 99.00
> 1 104 3030.00 100.00 99.00
> 2 102 2020.00 100.00 99.00
> 3 101 1010.00 100.00 99.00
> 4 105 1002.00 100.00 99.00
> 4 106 1002.00 100.00 99.00
> 4 107 1002.00 100.00 99.00
> 4 108 1002.00 100.00 99.00
> 5 109 1000.00 100.00 99.00
> (9 row(s) affected)
> --
> David Portas
> SQL Server MVP
> --

CR 8.5, VB6, Crviewer how to preset Copies

Ok, I know how to use printout feature and can set number of copies this is fine when going directly to printer, But I have endusers that want to preview the report befre printing.

They however make an easy mistake, the document they are previewing has a requirement of 3 copies when printed. The preview has no obvious way to set that and of course startup with 1 copy. I know I could add a line to run a printout of 2 copies but the previewer form is used by more than one report.

I just want to know is there an easy way to set the copies in the previewer print.

Thanks in advance.This code goes into the VB form that your CRViewer is located. I named mine CRViewer. From the Left drop down list in your code window, choose CRViewer (or whatever you named it), in the right Dropdown list, choose PrintButtonClicked.

Private Sub CRViewer_PrintButtonClicked(useDefault As Boolean)

Dim intCopies As Integer

useDefault = False

intCopies = 3

Report.PrintOut False, intCopies

End Sub